x - 4 APEX
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
3x2 + 6x - 24First factor out any common factors of the three terms. In this case, each term is a multiple of 3. So,3x2 + 6x - 24 = 3(x2 + 2x - 8)Next, use the reverse FOIL method to factor the polynomial in the parenthesis (x2 + 2x - 8). x2 factors out to x * x:(x + ??)(x + ??)Now, we must find two numbers that add to get 2 (from the 2x) and multiply to get -8. Those numbers are -2 and 4. So,(x2 + 2x - 8) = (x - 2)(x + 4)So,3x2 + 6x - 24 = 3(x - 2)(x + 4)
x2 + 6x + 8 = (x + 4)(x + 2)
X - 4
x2 + 6x + 8 =(x + 2)(x +4)
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
4
4(x2 - 6x + 13)
x - 4 APEX
(x - 2)(x - 4)
(X + 2)(X + 4) Factored
You didn't bother to list the binomials to choose from, but the two binomial factors of x2 + 6x - 40 are (x + 10) and (x - 4)
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)