To factor the polynomial 2x^2 + 16, we first look for a common factor. In this case, both terms are divisible by 2, so we can factor out a 2 to get 2(x^2 + 8). Next, we check if the remaining quadratic expression x^2 + 8 can be factored further. Since x^2 + 8 cannot be factored further over the real numbers, the factored form of the polynomial is 2(x^2 + 8).
It is: 2x(2x+11)
(2x - 9)(2x - 9)
2x+5x-24 7x2-24
x2 - 2x - 24 = (x - 6)(x + 4)
(3x + 4)(2x - 1)
It is: 2x(2x+11)
(x + 1)(2x - 5)
Depending on the missing operational sign, that would be 2(x plus or minus 8)
(2x - 9)(2x - 9)
(2x + 5)(2x - 5)
2x+5x-24 7x2-24
x2 - 2x - 24 = (x - 6)(x + 4)
The common factor is 2.
(3x + 4)(2x - 1)
45
(x+4)(x-2)
(2x - 1)(2x + 3)