To factor the polynomial 2x^2 + 16, we first look for a common factor. In this case, both terms are divisible by 2, so we can factor out a 2 to get 2(x^2 + 8). Next, we check if the remaining quadratic expression x^2 + 8 can be factored further. Since x^2 + 8 cannot be factored further over the real numbers, the factored form of the polynomial is 2(x^2 + 8).
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Oh honey, that's not a polynomial. It looks like you're missing an operator there. If you meant 2x^2 - 16, you can factor it as (2x + 4)(x - 4). But if you actually meant 2x * 16, well, there's nothing to factor there because it's just a multiplication problem.
It is: 2x(2x+11)
(2x - 9)(2x - 9)
2x+5x-24 7x2-24
x2 - 2x - 24 = (x - 6)(x + 4)
(3x + 4)(2x - 1)