(x + 1)(2x - 5)
2x2-3x-5 = (2x-5)(x+1) when factored
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
The factors are -1(2x + 1)(3x + 4)
(x - 8)(3x + 4)
(2x - 5)(x + 1) or (2x + 5)(x - 1) depending on the sign of the term 3x
The expression (2x^2 - 3x) is a quadratic polynomial in standard form, where (2x^2) represents the quadratic term and (-3x) is the linear term. To factor it, you can take out the common factor (x), resulting in (x(2x - 3)). This expression can be analyzed for its roots or further manipulated depending on the context.
x(3x - 2)
6x2 + 10x = 2x*(3x + 5)
(3x + 1)(x - 5)
3x(2x + 1)
2x2-3x-5 = (2x-5)(x+1) when factored
(3x + 4)(2x - 1)
(x - 1)(3x + 5)
(x - 2)(2x + 7)
6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)
(x + 3)(3x - 2)
To find the roots of the polynomial (3x^5 + 2x^3 + 3x), we can factor out the common term, which is (x): [ x(3x^4 + 2x^2 + 3) = 0. ] This shows that (x = 0) is one root. The quartic polynomial (3x^4 + 2x^2 + 3) does not have real roots (as its discriminant is negative), meaning it contributes no additional real roots. Therefore, the polynomial has only one real root, which is (x = 0).