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Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)

Q: How do you factor x cubed plus 9x squared plus 2x plus 18?

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2(4x - 3)(x + 3)

(x - 3)(x^2 + 6)

b= 10

The given expression can be simplified to: 3X squared +27

(12x2 + 18) / (3x2 + 6) = (4x2 + 6) / (x2 + 2)

Related questions

5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5

2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222

If that's -18y2, the answer is (3x - 2y)(x + 9y)

12 squared plus 18 squared is equal to 468.

2(4x - 3)(x + 3)

(x2 + 7x - 18) = (x + 9)(x - 2)

(x - 3)(x^2 + 6)

6(3r^2 - 14r + 3) and (2c + 1)(c - 9)

b= 10

The given expression can be simplified to: 3X squared +27

X2 + 3X - 18 Ask yourself, what two factors of - 18 add to 3? (X + 6)(X - 3) -----------------

If you're solving for b, then you use the quadratic formula to factor out b. In this case, b= -1/4 or -18/12