x2-15x+54
factor pairs of 54:
1,54
2,27
3,18
6,9
-1,-54
-2,-27
-3,-18
-6,-9 <-6 and -9 sum to -15
x2-6x - 9x+54
x(x-6) - 9(x-6)
(x-6)(x-9)
(x - 6)(x + 9)
57
54 = 1 x 54 54 = 2 x 27 54 = 3 x 18 54 = 6 x 9
(x - 6)(x - 9)
45 + x + 54 + x 2x + 99
(x-6)(x-9) I did that by factoring 54 until I found two numbers that added up to 15.
x2 + 15x + 54 = (x + 6)(x + 9) or (x + 9)(x + 6) since 6*9 = 54 and 6 + 9 = 15However, commutativity is implicit in deriving this factorisation so that the two factorisations are the same.or factor by groupingx2 + 15x + 54= x2 + 6x + 9x + 54= (x2 + 6x) + (9x + 54)= x(x + 6) + 9(x + 6)= (x + 6)(x + 9)
(5 x 6) + (9 x 6) = 14 x 6 = 84
2 x 3 x 3 x 3 = 54
(6 x 9) + (3 x 9) = 9 x 9 = 81 (2 x 27) + (1 x 27) = 3 x 27 = 81
6 x 9 = 54
(x - 9)(x + 6)