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(x-6)(x-9)

I did that by factoring 54 until I found two numbers that added up to 15.

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Q: How do you factor the trinomial x2 - 15x plus 54?

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It is: 126 plus 54 = 180

2a^3 + 54 can first be factored into 2 (a^3 + 27). This can then be factored out to 2 (a + 3) (a^2 - 3a + 9).

18 + 18 + 18 = 54

45 + x + 54 + x 2x + 99

54 + 78 = 132

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(x - 6)(x - 9)

x2 + 15x + 54 = (x + 6)(x + 9) or (x + 9)(x + 6) since 6*9 = 54 and 6 + 9 = 15However, commutativity is implicit in deriving this factorisation so that the two factorisations are the same.or factor by groupingx2 + 15x + 54= x2 + 6x + 9x + 54= (x2 + 6x) + (9x + 54)= x(x + 6) + 9(x + 6)= (x + 6)(x + 9)

x2-15x+54 factor pairs of 54: 1,54 2,27 3,18 6,9 -1,-54 -2,-27 -3,-18 -6,-9 <-6 and -9 sum to -15 x2-6x - 9x+54 x(x-6) - 9(x-6) (x-6)(x-9)

This question does not make sense. If it should be X2 x 15X -54, the answer is: X2 -15X + 54 = (X - 6)(X -9)

hi

Since 27 is a factor of 54, it is automatically the GCF.

6 is a factor of 54.

No, 54 is a factor of 108.

(x - 6)(x + 9)

57