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That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 1 plus or minus i where i is the square root of negative one.
What else can I help you with?
How do you factor 2x squared plus 3x minus 14?
(x - 2)(2x + 7)
How do you factor 2x squared plus x minus 6?
(2x - 3)(x + 2)
What is the factor of 2x squared minus 5x plus 3?
(2x-3)(x-1)
Who can factor 2X squared minus 11X plus 9?
(x - 1)(2x - 9)
How do you factor 2x squared plus 4x minus 1?
There is no rational factorisation.
How do you factor this expression 2x squared minus 7x plus 6?
(x - 2)(2x - 3)
How do you factor 4x squared minus 36x plus 81?
(2x - 9)(2x - 9) or (2x - 9)2
How do you factor 3x squared plus 9x minus 2x minus 6?
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
How do you factor 2x squared minus 5x minus 3?
2x squared - 5x - 3 = (2x +1)(x -3)
How do you factor 4x squared minus 2x?
2x(2x - 1)
How do you factor 5x squared plus 2x minus 7?
(x - 1)(5x + 7)
How do you factor 10x squared plus 11x minus 8?
(2x - 1)(5x + 8)
