Q: How do you factorise 24x 36?

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It is: 6(4x+3)

38

It is: 12(2x+3) when factored

3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4

The answer is, 24x

(24x)^5 - (24x)^3 + (16x)^2 - 16 This can be simplified multiple ways: 1. pull (24x)^3 out of the first two terms and 16 out of the second two. (24x)^3((24x)^2-1) + 16(16x^2-1) 2. just pull 8 out of everything 8(3*(24x)^4-3*(24x)^2+32x^2-2) ...

24x - 7 = 17

GCD(15x, 24x) = 3x

24x^5 + 24x^3 = 24x^3(x^2 + 1)

Find the GCF of 24a and 36. Since the a variable is not part of the 36 term, a will not be part of the GCF. So, we just need to find the GCF of 24 and 36, which is 12. So, factor 12 from both terms24a + 3612(2a + 3)

5x^2-24x+11

3x2-24x-48 is not factorable.