The terms in x in the factorisation must be 3 and 1, the whole numbers must be factors of 48 ie 1/48, 2/24, 3/16, 4/12, or 6/8. The only ones which can combine with the 3 to give a sum of 24 are 4 and 12 viz: (3x + 12)(x + 4)
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
x² + 8x - 48 = (x + 12)(x - 4) x² + 8x + 48 = (4+(√32)i)(4-(√32)i)
8r + 17 = 65 8r = 65 - 17 8r = 48 r = 48 / 8 r = 6
3x2-24x-48 is not factorable.
(3x-12)(x-4)
24x. For example, if x is 2, then 24x equals 48.
Make it easier, divide by 3: 3(x2 - 8x - 16) This is as far as it goes. (Quadratic formula gives roots as 9.66 and -1.66)
By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32
3x2 + 24x + 48
3x2 + 30x + 48 is a quadratic polynomial. If 3x2 + 30x + 48 = 0, then: 3(x + 2)(x + 8) = 0 ⇒ x + 2 = 0 → x = -2 or x + 8 = 0 → x = -8
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
I guess that should be 3 times (x squared) minus 48: 3x2 - 48 = 3(x2 - 16) = 3(x + 4)(x - 4)
144
It is 4 terms of an algebraic expression.
The idea is to solve the equation -3x2 + 24x - 19 = 0. You can use the quadratic formula for this, using a = -3, b = 24, c = 19. Or complete the square since dividing by -3 will give us 8x, an even coefficient. -3x2 + 24x - 19 = 0 (add and subtract 48 to the left side) -3x2 + 24x -48 + 29 = 0 (subtract 29 to both sides, and factor out -3) -3(x2 - 8x + 16) = -29 (divide by -3 to both sides) (x - 4)2 = 29/3 x - 4 = ± √(29/3) (add 4 to both sides) x = 4 ± √(29/3) (multiply by 3/3 inside the radical, if you want to rationalize the denominator) x = 4 ± (√87)/3