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Find the GCF of 24a and 36. Since the a variable is not part of the 36 term, a will not be part of the GCF. So, we just need to find the GCF of 24 and 36, which is 12. So, factor 12 from both terms
24a + 36
12(2a + 3)
It is: 3(t+3)
It is: 6(4x+3)
(x + 2)(x + 1)
You don't. There is no way to factorise it.
j
24a + b2 + 3a + 2b2= 27a + 3b2
38
(a + 6)(a + 4)
(3a - 4)(3a - 4)
X=5
p2+10d+7
(x+5)(x+3)
4c(-sq+2)
the answer is x(3+y)
4(x2 + 4)