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In a triangle ABC, when hypotenuse is 128 unit which is right angled at A.

By phythagoras theorem

H square = P square + B square

root of hypotenuse = ROOT of 8square + root of 8square

it means other two sides are equal

therefore . assuming the sides equal to x

we have 2x square=128

x square= 64

x = -+8

but length is always positive.

therefore other two sides = x= 8

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Q: How do you figure out the angles if the hypotonuse is 128?
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