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The "solution" depends on what the question is.
If you mean the roots, and if the equation of the parabola isy = ax^2 + bx + c then the roots are
[-b +/- sqrt(b^2-4ac)]/(2a)
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How do you find the endpoints of a parabola when you have the function of the line?
A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.
Can you solve X2 plus Y equals 63?
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.
How do you draw a parabola on an equilateral triangle?
To graph a parabola you must find the axis of symmetry, determine the focal distance and write the focal as a point, and find the directrix. These are all the main points you need to be able to draw a parabola.
How do you find a parabola opening up or down?
If you can mash the equation for the parabola into the form Y = Ax2 + Bx + C, then the parabola opens up if 'A' is positive, and down if 'A' is negative.
To find the value of a in a parabola opening up or down, subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
right
How do you find the endpoints of a parabola when you have the function of the line?
A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
How do you find the equation of a parabola if you know the equation of the tangent that touches it?
You need more than one tangent to find the equation of a parabola.
Can you solve X2 plus Y equals 63?
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.
How do you draw a parabola on an equilateral triangle?
To graph a parabola you must find the axis of symmetry, determine the focal distance and write the focal as a point, and find the directrix. These are all the main points you need to be able to draw a parabola.
How do you find a parabola opening up or down?
If you can mash the equation for the parabola into the form Y = Ax2 + Bx + C, then the parabola opens up if 'A' is positive, and down if 'A' is negative.
To find the value of a in a parabola opening up or down, subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
right
To find the value of a in a parabola opening left or right subtract the x value of the parabola at the vertex from the x value of the point on the parabola that is one unit the vertex?
Above
How do you find the gradient of a parabola?
(-1.5,0) (1.5,0) what is the gradient?
How do you find points on a parabola to graph them?
Select a set of x values and find the value of y or f(x) - depending on how the parabola is defined. These are the values that you need to graph.
Which graph could be used to find the solution of the system of equations y equals 2x plus 6 and y equals x2 plus 4x plus 3?
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
How do you find the zeros in a parabola?
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
