0
How do you find the equation of a parabola if you know the equation of the tangent that touches it?
Wiki User
∙ 12y ago
You need more than one tangent to find the equation of a parabola.
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
How do you find the equation for a parabola?
u look at it.... :-) hey I'm learning about parabolas too
How do you find the solution of a quadratic equation graphically?
You write the equation in such a way that you have zero on the right side. Then you graph the expression on the left side of the equal sign, and check where it touches the x-axis. Note that this method works for most common equations.
Find the area S of the region bounded by the parabola y 5x2 the tangent line to this parabola at 2 20 and the x-axis?
First we need to find the equation of the tangent line to the parabola at (2, 20).Step 1. Take the derivative of the function of the parabola.Let f(x) = 5x^2f'(x) = 10xStep 2. Find the slope of the tangent line at x = 2. Evaluate f'(2).f'(2) = 2 x 10 = 20Step 3. Using the slope, m = 20, and the point (2, 20), find the equation of the tangent line at that point. Use the point-slope form of a line(y - y1) = m(x - x1)(y - 20) = 20(x - 2)y - 20 = 20x - 40 add 20 to both sidesy = 20x - 20Step 4. Find the points of intersections of y = 5x^2 and y = 20x - 205x^2 = 20x - 20 Divide by 5 to both sidesx^2 = 4x - 4 subtract 4x and add 4 to both sidesx^2 - 4x + 4 = 0 factor(x - 2)^2= 0x = 2Step 5. Find the intersection of the tangent line with x-axis.y = 20x - 20y = 020x - 20 = 0x = 1Since the vertex of the parabola is (0, 0) and the intersection of the tangent line with parabola is (2,20) we use the interval [0, 2] to fin the required area.Step 6. IntegrateA = ∫ [(5x^2)] dx, where the below boundary is 0, and the upper boundary is 2 minus A= ∫ (20x + 20)] dx from 1 to 2= 10/3
How do you find the zeros in an equation by looking on a graph?
They are all the points where the graph crosses (or touches) the x-axis.
How do you find the equation of a parabola in standard form with x intercepts at 0 and 0 passing through 7 and 8?
y = 8/49*x2
Find the equation of chord of contact tangent to the parabola?
y=1/2(p+q)x-apq or x1x=2a(y+y1)
How do you find the tangent of a circle?
a tangent is a line that touches the circle at only ONE point
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
What is the slope of a parabola?
a parabola doesn't have one slope, the slope is constantly changing as you move accross the graph. however, it is possible to find a slope to a line tangent to a point on a parabola. to do this, take the derivative of the equation for the given parabola. then, take the X,Y coordinate and plug in the x value for the point. So, if the graph of of the equation was given by y=x^2, the derivative would be dy/dx=2x. you would then take a point, e.x. (2,4) and plug in the x value, 2, into dy/dx=2x, yielding a slope of 4 for the line tangent to that point.
How do you find the point of tangency?
A tangent is an object, like a line, which touches a curve. The tangent only touches the curve at one point. That point is called the point of tangency. The tangent does not intersect (pass through) the curve.
An equilateral triangle is inscribed in a parabola with its vertex at the vertex of the parabola how do you find the length of the equilateral triangle?
First you need more details about the parabola. Then - if the parabola opens upward - you can assume that the lowest point of the triangle is at the vertex; write an equation for each of the lines in the equilateral triangle. These lines will slope upwards (or downwards) at an angle of 60°; you must convert that to a slope (using the tangent function). Once you have the equation of the lines and the parabola, solve them simultaneously to check at what points they cross. Finally you can use the Pythagorean Theorem to calculate the length.
Find the equation of the line tangent to when x equals 8?
The question is suppose to read: Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8
How do you find a parabola opening up or down?
If you can mash the equation for the parabola into the form Y = Ax2 + Bx + C, then the parabola opens up if 'A' is positive, and down if 'A' is negative.
Find the value of x in the equation x squared equals 6x minus 9?
(X-3)(X-3) Foil that and you will see tha X = 3. This is a parabola that touches the X axis at X = 3.
How do you find the equation for a parabola?
u look at it.... :-) hey I'm learning about parabolas too
How do you find the solution of a quadratic equation graphically?
You write the equation in such a way that you have zero on the right side. Then you graph the expression on the left side of the equal sign, and check where it touches the x-axis. Note that this method works for most common equations.
How do you find the zeros in a parabola?
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
