I think you mean distance traveled. Every tiny period "dt" of time, the distance gone is the velocity at that time, times dt. Plot velocity against time. Each little slice of velocity times dt is a slice of the area. So the total distance is the total area under the graph from time t=0 to the finish, or to whatever time you want. This is the principle behind the Integral Calculus.
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
The answer depends on what variables the graph shows.
The final velocity is (the initial velocity) plus (the acceleration multiplied by the time).
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
Yes.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
postion is the area under the slope
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
The answer depends on what variables the graph shows.
The final velocity is (the initial velocity) plus (the acceleration multiplied by the time).
if the acceleration is constant, then it is a parabola (a=V*t+(at^2)/2). if it isn't, and you are give it's formula in relation to time, then it is possible to find the distance formula by using higher level mathematics(integrals).
You subtract the initial velocity from the final velocity and divide by the time interval.
Without knowing initial velocity ? Hmmm. That could make it difficult.Our best advice would be to use what you do know to find what you're looking for.
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)