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How do you find instantaneous velocity from position time graph?
Wiki User
∙ 12y ago
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer.
Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
Wiki User
∙ 13y ago
Wiki User
∙ 12y agoThe gradient of the tangent to the graph at the instant in question.
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How do you find the distance from a velocity time graph?
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
How do you go from a position graph to a velocity graph?
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
How do you determine acceleration from a position vs. time graph?
if the acceleration is constant, then it is a parabola (a=V*t+(at^2)/2). if it isn't, and you are give it's formula in relation to time, then it is possible to find the distance formula by using higher level mathematics(integrals).
How to calculate distance from a velocity time graph?
You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown. For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector. All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
How do you find the time acquired by initial velocity in an acceleration -time graph?
t=(vf-vi)/a
What does a distance time graph allow you to find?
Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.
How can you find the instantaneous acceleration of an object whose curve on the velocity time graph is a straight line?
It is the gradient (slope) of the line.
How do you find an object's instantaneous on a distance vs time graph?
With great difficulty since the question does not specify what aspect of the object's instantaneous. Speed, position, acceleration?
How do you find the distance from a velocity time graph?
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
What is the difference between a velocity time graph and a position time graph?
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
Find position given velocity vs time graph?
postion is the area under the slope
How do you go from a position graph to a velocity graph?
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
How can you obtain the average velocity and instantaneous velocity from a displacement time graph?
To obtain the average velocity from a displacement-time graph, you can calculate the slope of the line connecting two points on the graph. Divide the change in displacement by the change in time. To obtain the instantaneous velocity, you need to find the slope of the tangent line at a specific point on the graph. Choose a point on the graph and draw a line tangent to the curve at that point. The slope of this tangent line will give you the instantaneous velocity at that specific point.
How can you obtain an average velocity and instantaneous velocity from a displacement-time graph?
The gradient of the tangent at that point, or if you know the equation of the line, the differential of the equation at that point.. This is similar but It is simpler: Step 1 -- From the distance-time graph, if you know what time you are particularly in, go to your time axis (should be the horizontal axis) and from this particular time (point) on the time axis, go vertically upwards until it intersects the graph. Step 2 -- At this point of intersection, go horizontally to the left and read the value of the point at which this horizontal line intersects the vertical axis. This is the distance travelled by the body/particle at the particular instant chosen. Step 3 -- To determine the instantaneous velocity, simply divide the distance (determined in Step 2) by the time (from Step 1).
Define speed at which an object is moving at a given instant time?
If the displacement of the object (its position) can be described as a functional or algebric equation, you can find the instant speed of this object by calculating the derivative of its displacement equation, knowing that speed is the first derivative of position and acceleration, its second.
How do you find the average velocity on a graph?
The answer depends on what variables the graph shows.
How do you find out instantaneous velocity and maximum height?
Take the derivative of the function.By plugging a value into the derivative, you can find the instantaneous velocity.By setting the derivative equal to zero and solving, you can find the maximums and/or minimums.Example:Find the instantaneous velocity at x = 3 and find the maximum height.f(x) = -x2 + 4f'(x) = -2xf'(3) = -2*3 = -6So the instantaneous velocity is -6.0 = -2x0 = xSo the maximum height occurs at x = 0f(0) = -02 + 4 = 4So the maximum height is 4.
