Assuming you mean its range is 10m, then use the equation:
v0 = sqrt(r*g/sin(2θ)), where r is its range, θ is its initial angle, and g is acceleration from gravity.
=sqrt(10m*9.8m/s2/sin(90))
=sqrt(98.0m2/s2)
=9.9m/s
Meters per second
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
the equation for average velocity a = s/t s = distance travelled t = time examples miles/hour, meters/sec
Using one of the three laws of mechanical motion : v2 = u2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, s is the distance. Then, 0 = 202 + 2 x (-1)s : 2s = 400 : s =200 meters. The puck will travel 200 meters.
You cannot. You need to know either the initial speed or angle of projection (A).
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
You kicked the rock with an initial velocity of 3.4 m/s.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
When you say initial speed I assume there will be accelleration. If so you could you: s = ut + 1/2at^2. or s = 1/2(u + v)t where s is distance in meters u is initial velocity in ms v is the final velocity in ms a is accelleration in ms^-2 t is time in s If there is no accelleration then s = ut
so what you need to do is find the velocity that the person enters the water and then use the equation v sub final squared = v sub initial squared + 2*acceleration(final distance-initial distance). final velocity is zero, find the initial velocity yourself and use 2 as the final distance where the initial distance is 0, solve for acceleration. Easy way: the decelleration would have been twice that provided by gravity because the diver decellerated to zero in half the distance of the dive. The diver starts at zero and hits max velocity in 4 meters then goes from max velocity to zero in 2 meters. 2 x 9.81 m/s2 = ___
Velocity equal distance divided by time. For example, an object that traveled 5 metes in 10 seconds had a velocity of 5/10 meters per second which is .5 meters per second. Velocity is speed in a direction. Sometimes a navigate or positive number is sufficient as the direction. Other times you will need to be more specific, such as .5 meters per second East or 1.3 meters per second 30 degrees East of North.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
If it is kicked at 30 degrees to the horizontal then it will travel 27.7 metres.
Yes. The first is a speed (or velocity), the second is a distance.
Distance: Meters (or metres) Speed & velocity (meters per second). velocity also needs a direction but that isn't defined by SI units.