by using a caliper
http://www.technologystudent.com/equip1/vernier3.htm
if you mean a cylinder with a hole through it like a pipe or tube, then it's pi x (Od2 - id2)/4 x h Od = outer diameter id = inner diameter
There must be some distances given between the outer square and the inner square... We'll then decrease the differences from the side of the outer square in order to get the side of the inner square. Thus, we can find the perimeter of the inner square as well.
Suppose the diameter of the disk is D cm so that the radius is D/2 = R cm. Suppose the diameter of the hole is d cm so that its radius is d/2 = r cm. Then the area of one side of te disc is pi*(R^2 - r^2) Therefore the total area of the two sides is 2*pi*(R^2 - r^2) square cm. This ignores the surface area of the edge which, although small, is not 0.
The radius is the distance from the center to the outer edge of the circle. You can measure the diameter, the distance from side to side, and divide by 2.
you double the radius to find the diameter.
Outer radius minus inner radius Subtract the inside diameter from the outside diameter, then divide the difference by 2.
Outer jaws are used. Inner jaws will be use to find the inner dia of the cylindrical vessel.
The bearing number can be checked out depends on the size of ID (Inner Diameter), OD (Outer Diameter) and H (Height) of this bearing.
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if you mean a cylinder with a hole through it like a pipe or tube, then it's pi x (Od2 - id2)/4 x h Od = outer diameter id = inner diameter
Inside a Castle.
PCD (Pitch Circle Diameter) is the diameter of a circle that goes through each of the bolt holes. You can find it by measuring distance from centre of one bolt hole to the centre of opposite end bolt hole...
There are both an inner and an outer seal. The outer seal is about 2" in diameter and the inner one about 1/2". The little one is hard to find and hard to put in. I have replaced the outter seal twice and still have a small leak - about a 10 of a qt every 100 miles. Bummer Ben
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
There must be some distances given between the outer square and the inner square... We'll then decrease the differences from the side of the outer square in order to get the side of the inner square. Thus, we can find the perimeter of the inner square as well.
You can find the most Iron and nickel in the earth's inner and outer core.
atmosphere/hydrospherelithosphereasthenospheremantleouter coreinner core(you could divide these further, but the above are the main 6 layers)