Q: How do you find out the sum of two integers?

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The integers are -34 and -33.

you add them together?

-- Ignore the signs for a moment. -- Find the difference of the two integers. -- Give it the sign of whichever integer is the bigger number.

There are two consecutive odd integers whose sum is 176. They are 87 and 89.

They are 2n+2

Related questions

The sum of the squares of two consecutive positive even integers is 340. Find the integers.

The sum of any two consecutive integers must be an odd number. So this question is incorrect.

Let the integers be 'n' & 'n+2' Hence Their squares are n^(2) & (n+2)^(2) Their sum is n^(2) + (n+2)^(2) = 74 Expanding n^(2) + n^(2) + 4n + 4 = 74 2n^2 + 4n -70 = 0 n^2 + 2n - 35 = 0 Factor (n - 7)(n + 5) Hence n = '5' & '7' Odd and consecutive.

The integers are -34 and -33.

you add them together?

There are two consecutive odd integers whose sum is 176. They are 87 and 89.

-- Ignore the signs for a moment. -- Find the difference of the two integers. -- Give it the sign of whichever integer is the bigger number.

The two integers are 6 and 7.

They are 2n+2

29 cannot be the sum of two odd integers. The sum of two odd integers is always an even integer.

To find the sum of two integers with different signs, you simply combine them, and give the result the sign of the larger integer. For example, you have two integers: -9 and +5. You combine them, that is the +5 cancels out 5 of the -9, leaving -4.

The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.