The two integers are 6 and 7.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
Let x = 1st integer, since consecutive even integer differs by 2 then the 2nd integer = x + 2. So we have, x + 4(x + 2) = 48 x + 4x + 8 = 48 5x = 40 x = 8 (1st integer) Thus, the integers are 8 and 10. Check.
The smaller integer is 6, the larger integer is 32
Let the two consecutive integers be n and n+1. Then, n + (n + 1) < 55 2n + 1 < 55 2n < 55 - 1 : 2n < 54 n < 27 The Inequality Statement can therefore be modified to show that for two consecutive integers to be less than 55 then the smaller integer must be less than 27.
44 & 45
The smaller integer is 17.
6+7=13 and 6 and 7 are consecutive. 6 is the smaller integer so answer is 6
The larger integer is 30. The smaller is 28.
The numbers are 9 and 10.
The sum is four.
x+3 and x+4 would be consecutive integers.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
-1
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
There can be no such integers: a smaller integer cannot be 5 times the larger number.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
3*(x+1) - x = 7 So 3x + 3 - x = 7 then 2x = 4 or x = 2 So the two integers are 2 and 3