There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
Let x = 1st integer, since consecutive even integer differs by 2 then the 2nd integer = x + 2. So we have, x + 4(x + 2) = 48 x + 4x + 8 = 48 5x = 40 x = 8 (1st integer) Thus, the integers are 8 and 10. Check.
The smaller integer is 6, the larger integer is 32
Let the two consecutive integers be n and n+1. Then, n + (n + 1) < 55 2n + 1 < 55 2n < 55 - 1 : 2n < 54 n < 27 The Inequality Statement can therefore be modified to show that for two consecutive integers to be less than 55 then the smaller integer must be less than 27.
Let the smaller integer be x, then then larger integer is x + 2, and: 3x + (x + 2) = 58 → 4x = 56 → x = 14 → The two integers are 14 and 16.
The smaller integer is 17.
6+7=13 and 6 and 7 are consecutive. 6 is the smaller integer so answer is 6
The larger integer is 30. The smaller is 28.
The sum is four.
The numbers are 9 and 10.
x+3 and x+4 would be consecutive integers.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
-1
There can be no such integers: a smaller integer cannot be 5 times the larger number.
3*(x+1) - x = 7 So 3x + 3 - x = 7 then 2x = 4 or x = 2 So the two integers are 2 and 3
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
Let x = 1st integer, since consecutive even integer differs by 2 then the 2nd integer = x + 2. So we have, x + 4(x + 2) = 48 x + 4x + 8 = 48 5x = 40 x = 8 (1st integer) Thus, the integers are 8 and 10. Check.