How do you find sin theta when tan theta equals one fourth?

Anonymous

∙ 12y ago

Updated: 8/20/2019

I will note x instead of theta

tan(x) = sin(x) / cos(x) = 1/4

sin(x) = cos(x)/4 = ±sqrt(1-sin2x)/4 as cos2x + sin2 x = 1

4 sin(x) = ±sqrt(1-sin2x)

16 sin2x = 1-sin2x

17 sin2x = 1

sin2x = 1/17

sin(x) = ±1/sqrt(17)

Wiki User

∙ 12y ago

What else can I help you with?

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