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Q: How do you solve 2 sin squared theta equals one fourth?

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If r-squared = theta then r = Â±sqrt(theta)

You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.

It also equals 13 12.

cos2(theta) = 1 so cos(theta) = Â±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0

Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.

cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1

Cosine squared theta = 1 + Sine squared theta

To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)

-1

Since there is no equation, there is nothing that can be solved.

Tan^2

The question contains an expression but not an equation. An expression cannot be solved.

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