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tan A says nothing about tan B without further information.
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What is 12 b plus 3 equals 39 b equals?
b = 12 12(3)+3 = 39, use a calculator to find out
If a equals b and b equals c then what does c plus b equals?
2a. (a, b and c are all equal.)
If a equals 3 and bequals minus 5 then a minus b equals?
If a equals 3 and b equals minus 5 then a minus b equals what
Can sine theta equals tan theta equals theta be true for small angles?
If sin θ = tan θ, that means cos θ is 1 (since tan θ = (sin θ)/(cos θ)) (Usually in and equation a/b=a, b doesn't have to be 1 when a is 0, but cos θ = 1 if and only if sin θ = 0) The angles that satisfy cos θ = 1 is 2n(pi) (or 360n in degrees) When n is an integer. But if sin θ = tan θ = θ, the only answer is θ = 0. Because sin 0 is 0 and cos 0 is 1 and tan 0 is 0 The only answer would be when θ = 0.
If A equals 6 what does b equals?
6 === the what does B =
If sin b equals to x over y where b is acute find tan b in terms of x?
tan(b) = x/sqrt(y^2-x^2)
If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
What is tan20tan32 plus tan32tan38 plus tan38tan20?
This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1
Diploma First Year Maths Important Questions List?
tan a=1/2 tan b=1/3 find tan (a-b)
A squared plus b squared equals 26 where a equals b find a and b?
a=b=3.60555
A varies jointly as b and c One set of values is a equals 2.4 b equals 0.6 and c equals 0.8 Find a when b equals 0.4 and c equals 0.4?
a = 0.8
Cos A equals one third. where A is greater than zero but less than pi over two. Sin B equals negative one half. where B is greater than negative pi over two but less than zero. Find Tan A plus B?
Ok, im not positive about this but here is what i got. (ca=cos(a),sa=sin(a),cb=cos(b)ect) ca=1/3 | ca^2=1/9 | sa^2=1-ca^2 | sa^2=8/9 | sa=.943 Sin(a)=.943 Cos(a)=.333 Tan(a)=2.832 sb=-1/2 | sb^2=1/4 | cb^2=1-.25 | cb^2=3/4 | cb=-.866 Sin(b)=-.5 Cos(b)=-.866 Tan(b)=.577 Tan(a+b)=(Tan(a)+Tan(b))/(1-2.832*.577) Tan(a+b)=3.41/-.634 Tan(a+b)=-5.376 So that's what i got. If you have any questions or if you got a different answer you should email me. actually email me regardless, i want to see if i got it right. allonbacuth@gmail.com
What is the exact trigonometric function value of cot 15 degrees?
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
How do you find the perimeter of a parallelogram with B equals 3.6 cm and S equals 2.2 cm?
It depends on what B is and what S is!
What is 12 b plus 3 equals 39 b equals?
b = 12 12(3)+3 = 39, use a calculator to find out
What is the measure of angle A to the nearest degree if side a equals 490 and side b equals 960?
There is not enough information. Angle A can be anything between 0 and 180 degrees. If you are talking about a triangle ABC, in which angle C is the right angle then a is the opposite side and b is the adjacent side. tan A = opposite / adjacent tan A = 490 / 960 = 0.51041666666666666666666666666667 and A = invtan(0.51041666666666666666666666666667) [also called tan-1] so A = 27.04 degrees
How to find the true bearing of the sun after calculating the LHA using azimuth method and using amplitude method?
Use the formula and find out A B C. If LHA is more than 180° P= 360 - LHA otherwise P= LHA A= Tan latitude÷Tan P B= Tan Declination÷ Sin P C is the resultant of A and B subtract the small value from the big and put the sign of bigger one (A or B) A IS NAMED OPPOSITE TO LET B IS NAMED SAME AS DECLINATION THEN APPLY THE Formula Tan Azimuth= 1/C×Cos lat And find true azimuth
