This may not be the most efficient method but ...
Let the three angle be A, B and C.
Then note that A + B + C = 20+32+38 = 90
so that C = 90-A+B.
Therefore,
sin(C) = sin[(90-(A+B) = cos(A+B)
and cos(C) = cos[(90-(A+B) = sin(A+B).
So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B)
Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)]
so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)]
The given expressin is
tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A)
= tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B)
substituting for cot(A+B) gives
= tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)]
cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression.
= tan(A)*tan(B) + [1- tan(A)*tan(B)]
= 1
It is approx 0.9725
It is 3/13 - 2/13*i
Without an equality sign it's not an equation but it can be simplified to: 7x-5
cotA*cotB*cotC = 1/[tanA+tanB+tanC]
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
The answer is 672.
27x3+6=87.
132
The answer to your question is 366.
It is 77
102
That is 27 x 9 = 243
189
No, it is not.
A plus + a plus is a plus.
43