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How do you find the Distance when a train moves with a uniform velocity of 36 kilometer hour for 10 seconds?
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How do you get velocity when time in seconds is 0.1 and distance is 8?
velocity=distance/time for uniform velocity. You need units for both the time and the distance to get a correct answer. Example: the speed limit is 65 miles/hour
How does the total distance changes as the total time increases in case of uniformly motio?
For uniform motion, distance = velocity*time where uniform implies that the velocity is a constant. Therefore distance = v*time and so, if time increases by t, the distance increases by vt.
How does constant velocity differ from constant acceleration?
Constant velocity is a measure of distance traveled per unit of time at a uniform speed, such as miles per hour or feet per second. Constant acceleration is a measure of a continuing increase in velocity per unit of time, as when a car speeds up from 30 miles per hour to 40 miles per hour in 5 seconds, then from 40 miles per hour to 50 miles per hour during the next 5 seconds. It will then have had a constant acceleration of 10 miles per hour per 5 seconds.
Can the average velocity of a body be the same as the instateneous velocity?
Yes, But in uniform motion only.
An airplane originally at rest on a runway accelerates uniformly at 6 meters per second for 12 seconds During this 12-second interval the airplane travels a distance of approximately?
The formula for distance covered during uniform acceleration isd = 1/2 * (vf + vi) * t (1)Time, t, is given; initial velocity, vi, is 0; but final velocity, vf, is unknown and must be computed from given information. Knowing the rate of acceleration, initial velocity and time, The final velocity may be computed using the formula for average acceleration (actual acceleration under uniform motion) which isa = (vf - vi) / t (2)Rewriting to solve for vf with vi = 0 we havevf = a * tvf = 6m/s2 * 12svf = 72m/sPlugging this value into equation (1) with the other given values we haved = 1/2 * (72m/s + 0 m/s) * 12sd = 432mSo the airplane will travel 432m from rest in 12 seconds under 6m/s uniform acceleration.
How do you get velocity when time in seconds is 0.1 and distance is 8?
velocity=distance/time for uniform velocity. You need units for both the time and the distance to get a correct answer. Example: the speed limit is 65 miles/hour
What is the formula for uniform velocity?
velocity is a vector quantity. Its magnitude is given by (velocity)= (distance)/(time)
How do you find distance with uniform velocity time final velocity and initial velocity?
If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
How does the total distance changes as the total time increases in case of uniformly motio?
For uniform motion, distance = velocity*time where uniform implies that the velocity is a constant. Therefore distance = v*time and so, if time increases by t, the distance increases by vt.
What is uniform velocity and uniform accelration?
If a car moving in a straight line travels equal distance in equal time no matter how small these distances may be, the car is said to be moving with a CONSTANT or Uniform Velocity.
When body have 2ms accleration in 15 seconds with a velocity 30ms does the velocity of the car uniform?
Although the question is stated in a somewhat confusing way, we can state withconfidence that the velocity of the car is NOT uniform, because a value is given forits acceleration. 'Uniform' motion means zero acceleration.
Does motion of seconds hand of a watch represent uniform velocity?
No. The direction changes all the time.
When do you say that the velocity of the car is equal?
when a car travels equal distance in equal intervals of time its velocity is uniform and equal
When a body is moving with uniform velocity what is difference between distance and time?
the distance will be equal to the time multiplied by a factor which is the speed.
What is the difference between uniform velocity and on uniform velocity?
I assume you mean "non-uniform". "Uniform" simply means that the velocity (in this case) doesn't change.
What is the objects average velocity over a 15 second interval if the object initially at rest experiences an acceleration of 1.7 for 6 sec and travels at that constant velocity for another 9 seconds?
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
What are the nature of the distance time graphs for uniform and non unifrm motion of an object?
A distance-time graph for an object moving at a constant velocity will be a straight line - the gradient of the line corresponds to the velocity. Non-uniform motion will cause the gradient of the line to change.
