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This is how you find the area of a regular pentagon:

Break it into five isosceles triangles by drawing lines from the middle of it to each vertex. Then, draw a line connecting the middle to the midpoint of a side. You can call that line the apothem. The apothem should break up one of the triangles into two smaller congruent right triangles. You can know the degrees in the triangle by dividing the central angle of 360 by 10, (dividing it by 10 because your smallest triangle you're going to use is 1/10th of the whole pentagon) So now you know the unknown angle towards the top of the smallest triangle is 36, do the subtraction so the unknown angle towards the bottom is 54. Now trig it out! SOH-CAH-TOA shows that tan(54)=(a/s). A being the apothem and s being the side length of the smallest triangle, which is half a side length. Now that you know the lengths of the smallest triangle, find the area of that. That triangle is replicated 10 times in the pentagon, so multiply it by 10.

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Q: How do you find the area of a common pentagon?
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