This is how you find the area of a regular pentagon:
Break it into five isosceles triangles by drawing lines from the middle of it to each vertex. Then, draw a line connecting the middle to the midpoint of a side. You can call that line the apothem. The apothem should break up one of the triangles into two smaller congruent right triangles. You can know the degrees in the triangle by dividing the central angle of 360 by 10, (dividing it by 10 because your smallest triangle you're going to use is 1/10th of the whole pentagon) So now you know the unknown angle towards the top of the smallest triangle is 36, do the subtraction so the unknown angle towards the bottom is 54. Now trig it out! SOH-CAH-TOA shows that tan(54)=(a/s). A being the apothem and s being the side length of the smallest triangle, which is half a side length. Now that you know the lengths of the smallest triangle, find the area of that. That triangle is replicated 10 times in the pentagon, so multiply it by 10.
The boy had to find the area and perimeter of the pentagon.
To find the area of a pentagon when you have a base height and a length, you can divide the pentagon into simpler shapes, such as triangles and rectangles. If you know the base length and the height from the base to the top vertex, you can use the formula for the area of the pentagon: Area = (Perimeter × Apothem) / 2, or apply the formula for the area of individual shapes you've divided it into. If the pentagon is regular, you can also use the formula for the area of a regular pentagon: Area = (1/2) × Perimeter × Apothem.
Area = 110.11 cm2
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
Since the question does not say so, you may not assume that the pentagon is regular. One way to find the area is to select any point inside the pentagon and join it to each of the vertices. This will divide the pentagon into 5 triangles. You can then measure the sides of each triangle and thereby calculate its area. Then sum the areas of the triangles. You could also select one side in each triangle as the base and then draw and measure the perpendicular distance to the opposite vertex. That is another way to find the area of each triangle. There are other methods, too. To find the perimeter you will need to measure the length of each side of the pentagon and add these lengths together.
Oh yes, it most definitely will. They're equal.
The boy had to find the area and perimeter of the pentagon.
To find the area of a pentagon when you have a base height and a length, you can divide the pentagon into simpler shapes, such as triangles and rectangles. If you know the base length and the height from the base to the top vertex, you can use the formula for the area of the pentagon: Area = (Perimeter × Apothem) / 2, or apply the formula for the area of individual shapes you've divided it into. If the pentagon is regular, you can also use the formula for the area of a regular pentagon: Area = (1/2) × Perimeter × Apothem.
Area = 110.11 cm2
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A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
If you mean a pentagonal prism, then find the area of the pentagon 1st. Length of 1 side x 1.7, then multiply by the height of the prism. But I dont really know the regular Pentagon volume. sorry... hope you dont hate me for that.
surface area= b x h actually no its 5(a)(s)+5(s)(h) s is side and h is height only problem i dont know what a is
Since the question does not say so, you may not assume that the pentagon is regular. One way to find the area is to select any point inside the pentagon and join it to each of the vertices. This will divide the pentagon into 5 triangles. You can then measure the sides of each triangle and thereby calculate its area. Then sum the areas of the triangles. You could also select one side in each triangle as the base and then draw and measure the perpendicular distance to the opposite vertex. That is another way to find the area of each triangle. There are other methods, too. To find the perimeter you will need to measure the length of each side of the pentagon and add these lengths together.
If 6 is the side of a regular pentagon, the area is 61.937
A pentagon is a 2-D shape. You can't find the volume of it unless it's 3-D. The formula for the area of a pentagon has something to do with the perimeter, the number of sides, the apothem, and the number 2.
Given only the information in the question, there is no option but to measure the pentagon at the base and calculate its area.