A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
The answer is 171.275*apex*
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
Area = 440.44 sq feet
85.30
A regular tetrahedron, with edges of length 1 units, has a total surface area of sqrt(3) square units.
A regular pentagon with a radius (apothem) of 5.1 units cannot have sides of 7.5 units and, conversely, a regular pentagon with sides of length 7.5 units cannot have a radius of 5.1 units. The figure is, therefore, impossible.
The answer is 171.275*apex*
Apothem length: 4.82 35.35 square units APEX
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
In the inradius is 18 units then the area is 1177 square units.
Area = 440.44 sq feet
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
85.30
A regular tetrahedron, with edges of length 1 units, has a total surface area of sqrt(3) square units.
389.40
293.72
309.12