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Q: How do you find the area of a three dimensional square?
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To find the surface area of the three dimensional figure you must find the perimeter of a face and then multiply by the height?

NO. This is the way to get the volume of a prism, not the surface area of any three-dimensional figure. To find the surface area of a three-dimensional figure, you must find the area of each of its faces and then add the side-areas together.


What is the formula for finding lengths of a square when you are given a volume?

None exist. A square is a measurement of area, length is a linear measurement and volume is a capacity. To find the lengths of a square from the area, take the square root of the area. To find the lengths of a cube from the volume, take the cube root of the volume. To clarify: Area refers to a two-dimensional space. Volume is three dimensional, and thus appropriate for a cube or ball, not a square or circle.


To find the surface area of a three dimensional figure what do you have to find?

You need to find the area of each two dimensional surface on the figure. Do you have a specific figure in mind?


Why does length width and height equal volume?

A square has width and height. Width is the horizontal line, height is the vertical line. This is a two-dimensional object and has an area.A cube is a square with one more dimension, length, which makes it a three dimensional object. As a three-dimensional object, it no longer has an area, but now has volume.To find the area of a cube (a three-dimensional object), one must multiply three dimensions (length, width, and height) to obtain the volume of the cube.


Is it true that to find the surface area of a three dimensional figure you must find the area of each of its faces and then add them together?

TRUE: To find the surface area of a three dimensional figure, you must find the area of each of its faces and then add them together.


Is it true that to find the surface area of a three dimensional figure you must find the area of each of its faces and then multiply them together?

False.To find the surface area of a three-dimensional figure, find the area of the faces and add them together.


Why can you not find the volume of an circle by multiplying the length by its width by its height?

A circle is not three-dimensional. It is a two-dimensional shape than can have an area, but not a volume. A column or cannister would have calculable volumes because they are three-dimensional shapes.To find the area of any circle, just remember 'Pie are square'. Of course, everybody knows that cakes are square and pies are round, but this is a different sort of pie. It is actually spelled pi. And the 'are' is actually an 'r' to signify 'radius'. In math, when we 'square' something, we are multiplying it by itself.


What is the answer to To find the surface area of a three-dimensional figure you must find the area of each?

... face and add them together.


How do you find the voulme of a rhombus?

Rhombi are two dimensional, but the easiest way to find the area is to treat it like a parallelogram, or even a square. Just find Base x Height and you will get the area of a two dimensional rhombus, square, or parallelogram (among other polygons).Since volume is a three dimensional property, and rhombi are two dimensional, I will assume you just have an extruded rhombus. If I am correct, then you can just add the depth to that formula, giving you Base x Height x Depth.


How does knowing the area of two-dimensional figures help you find the surface area of a three-dimensional shape?

The surface area of the 3-D figure will be the total of the areas of the 2-D figures.


Is it true that to find the surface area of a three dimensional figure you must find the area of each of it faces and multiply together?

No, you must add, not multiply.


How do you find square-meter of length?

This question doesn't make any sense. A square metre is a two dimensional measurement of area not a one dimensional measurement of length. The two are incompatible - so you cannot have any square metres in a length.