Find the areas of the rectangles and triangles. Add them together.
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You could consider the cross as two intersecting rectangles. Calculate the area of both rectangles and the area of the intersection (overlap). Then area of cross = sum of the areas of the rectangles minus the area of the overlap.
Assuming you have the dimensions of each of the sides - treat it as two separate rectangles. Using the measurements you have, work out the areas of both rectangles - then add them together.
Rectangles are related to the distributive property because you can divide a rectangle into smaller rectangles. The sum of the areas of the smaller rectangles will equal the area of the larger rectangle.
One method is to divide it into regular shapes - rectangles, triangles, etc. - and measure the areas of those shapes.
The areas are proportional to the square of the scale factor.
10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2
An L-shaped area can be divided into two rectangles. The total area is the sum of the areas of the two rectangles.
I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.
Split the area up into shapes for which you can work out the area: rectangles and triangles. Then the area of the original room is the sum of all the areas.
Some rectangles don't have equal sides.