First square the face diagonal
Then multiply the result by 3
Next divide that by 2
And finally take the positive root to get the body diagonal
The answer will depend on the information that you have: the volume of the cube, the total surface area, the surface area of one face, the major diagonal, a minor diagonal or some other characteristic.
Each face of a cube is a square.Each face of a cube is a square.Each face of a cube is a square.Each face of a cube is a square.
Looking for a quick answer? It's...x√(3)2Looking for an explanation, too? It's below.If the cube's sides are length x, and if we create a right triangle using two of the edges, then a diagonal of one of the faces, by the Pythagorean Theorem, is x√(2).a2+b2=c2x2+x2=c22x2=c2√(2x2)=√(c2)c = √(2x2)c = x√(2)So if the diagonal of a face of a cube is x√(2), and if we create a triangle with the sides of that diagonal, any side not on its face, and the diagonal in the middle of the cube connecting them, we can use the Pythagorean Theorem again.a2+b2=c2(x√(2))2+x2=c22x2+x2=c2√(3x2)=√(c2)c = √(3x2)c = x√(3)That is the length of a diagonal of the cube. Since the center is halfway through that diagonal and a corner is at the end, simply dividing by 2 will do the trick.x√(3)2Just replace x with whatever the length of the side is, and you have your distance from a vertex to the center.
Approximately 1.73 m/s Applying the Pythagorean theorem twice, you find that the diagonal of a cube with edge of length s is: s*sqrt(3). [The diagonal of a face of a cube, dface, is found by: (dface)2=s2+s2=2s2 --> dface=s*sqrt(2). dcube is find by applying the Pythagorean theorem to the triangle comprising sides of the diagonal of a face, an edge of the cube, and the diagonal of the cube: (dcube)2=(dface)2+s2=2s2+s2=3s2 --> dcube=s*sqrt(3) The speed of the insect is distance/time=5*sqrt(3)/5=sqrt(3) seconds, or approximately 1.73 m/s.
A cube has 6 face's
A cube with a face diagonal of 25cm has a surface area of 1875cm2
The distance between two tetrahedral voids is 0.866*edge length of the cube.As tetrahedral voids are present at 1/4th of the distance from each corner on a body diagonal of a cube.On each body diagonal there are two tetrahedral voids so making a total of 8 tetrahedral voids in an FCC cube. the distance between two tetrahedral voids is half of the body diagonal of a cube and the body diagonal of a cube is1.732 times of the edge length of the cube
The answer will depend on the information that you have: the volume of the cube, the total surface area, the surface area of one face, the major diagonal, a minor diagonal or some other characteristic.
find the cube root of 125(which is 5) is the length of one side do Pythagorean theorem to find the diagonal 5squared plus 5 squared=50 square root of 50=7.07106781 is diagonal
Each face of a cube is a square.Each face of a cube is a square.Each face of a cube is a square.Each face of a cube is a square.
Side lengths = 10.7289 units Face diagonal = 15.173 units Surface area = 690.657 units2
It is sqrt(3) times length of an edge. How to figure. The diagonal across one face is sqrt(2) * edge [make a right triangle: the hypotenuse will be that diagonal]. Now make another right triangle, with the diagonal across the face as one 'leg', and an edge as the other 'leg'. The hypotenuse of this triangle will be a diagonal of the cube: Length of this = sqrt((leg1)2 + (leg2)2) = sqrt((edge)2 + (sqrt(2)*edge)2) = sqrt(edge2 + 2*(edge)2) = sqrt(3*(edge)2) = sqrt(3)*(edge)
Looking for a quick answer? It's...x√(3)2Looking for an explanation, too? It's below.If the cube's sides are length x, and if we create a right triangle using two of the edges, then a diagonal of one of the faces, by the Pythagorean Theorem, is x√(2).a2+b2=c2x2+x2=c22x2=c2√(2x2)=√(c2)c = √(2x2)c = x√(2)So if the diagonal of a face of a cube is x√(2), and if we create a triangle with the sides of that diagonal, any side not on its face, and the diagonal in the middle of the cube connecting them, we can use the Pythagorean Theorem again.a2+b2=c2(x√(2))2+x2=c22x2+x2=c2√(3x2)=√(c2)c = √(3x2)c = x√(3)That is the length of a diagonal of the cube. Since the center is halfway through that diagonal and a corner is at the end, simply dividing by 2 will do the trick.x√(3)2Just replace x with whatever the length of the side is, and you have your distance from a vertex to the center.
Approximately 1.73 m/s Applying the Pythagorean theorem twice, you find that the diagonal of a cube with edge of length s is: s*sqrt(3). [The diagonal of a face of a cube, dface, is found by: (dface)2=s2+s2=2s2 --> dface=s*sqrt(2). dcube is find by applying the Pythagorean theorem to the triangle comprising sides of the diagonal of a face, an edge of the cube, and the diagonal of the cube: (dcube)2=(dface)2+s2=2s2+s2=3s2 --> dcube=s*sqrt(3) The speed of the insect is distance/time=5*sqrt(3)/5=sqrt(3) seconds, or approximately 1.73 m/s.
If a face on a cube is 49 square meters the cube's volume is: 343 m3
All faces on a cube are equal to each other the shape is of the face on a cube is a square
A cube is the 3-dimensional counterpart of a square. Each face of a cube is equal to all the others. This means that each face is a square.