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What is the exact value of cotangent 150 degrees?
Using the Circle Unit which is a chart used in precal and calc classes, you can see that angle 150 in radians is 5pi/6. Using this, the cot value is -Root3.
What is tan 5pi over 8 times R to the nearest thousandth and how can you find this on a scientific calculator?
You cannot because you do not know what R is.
What is the diameter of a circle with a circumference of 5pi cm?
5cm
What is the exact answer to the sine of 5pi 12?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. However, I am assuming the question is about sin (5pi/12). If not, please resubmit your question spelling out the symbols as "plus", "minus", "times" sin(5pi/12) = sin(pi/4 + pi/6) = sin(pi/4)*cos(pi/6) + cos(pi/4)*sin(pi/6) = √2/2*√3/2 + √2/2*1/2 = √2(√3 + 1)/4
How do you find the general solution for cos of 3x- pi over 3 equals 0.5?
cos (3pi x/3) = 0.5 The number of answers depends on the range of angles. I will solve this question using the range 0<x<2 pi. Draw a unit circle, you will see that the quadrants where cosine gives a positive value are the first and the fourth quadrants. The Angles whose cosines give + 0.5 are: pi / 3 and 5pi / 3. (Note that 7 pi/3 and 11 pi/3 are also possible solutions but they lie out of the range 0<x<2pi.) 3pi x/3 = pi/3 OR 3pi x/3 = 5pi/3 Here you can solve the equations to give x = 1/3; 5/3
What is the exact value of cotangent 150 degrees?
Using the Circle Unit which is a chart used in precal and calc classes, you can see that angle 150 in radians is 5pi/6. Using this, the cot value is -Root3.
What is tan 5pi over 8 times R to the nearest thousandth and how can you find this on a scientific calculator?
You cannot because you do not know what R is.
Which of these angles is coterminal with 32?
-5pi/2
What is the diameter of a circle with a circumference of 5pi cm?
5cm
What is the exact answer to the sine of 5pi 12?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. However, I am assuming the question is about sin (5pi/12). If not, please resubmit your question spelling out the symbols as "plus", "minus", "times" sin(5pi/12) = sin(pi/4 + pi/6) = sin(pi/4)*cos(pi/6) + cos(pi/4)*sin(pi/6) = √2/2*√3/2 + √2/2*1/2 = √2(√3 + 1)/4
Find Length of an arc of circle when measure of arc is 50 and radius is 3.5?
We have a formula of finding the arc length, s = θr, where s is the length of the intercepted arc, θ is the central angle measured in radians, and r is the radius of the circle. So that we need to convert 50 degrees in radians. 1 degrees = pi/180 radians 50 degrees = 50(pi/180) radians = 5pi/18 radians s = θr (replace θ with 5pi/18, and r with 3.5) s = (5pi/18)(3.5) = (17.5/18) pi ≈ 3 Thus, the length of the arc is about 3.
How do you find the general solution for cos of 3x- pi over 3 equals 0.5?
cos (3pi x/3) = 0.5 The number of answers depends on the range of angles. I will solve this question using the range 0<x<2 pi. Draw a unit circle, you will see that the quadrants where cosine gives a positive value are the first and the fourth quadrants. The Angles whose cosines give + 0.5 are: pi / 3 and 5pi / 3. (Note that 7 pi/3 and 11 pi/3 are also possible solutions but they lie out of the range 0<x<2pi.) 3pi x/3 = pi/3 OR 3pi x/3 = 5pi/3 Here you can solve the equations to give x = 1/3; 5/3
What are all the exact values for which tan t equals sqrt3?
sin(60) or sin(PI/3) = sqrt(3)/2 cos(60) or cos(PI/3)=1/2 tan(60) or tan(PI/3) = sin(60)/cos(60)=sqrt(3) But we want tan for -sqrt(3). Tangent is negative in quadrant II and IV. In Quadrant IV, we compute 360-60=300 or 2PI-PI/3 =5PI/3 tan(5PI/3) = -sqrt(3) Tangent is also negative in the second quadrant, so we compute PI-PI/3=2PI/3 or 120 degrees. tan(t)=-sqrt(3) t=5PI/3 or 2PI/3 The period of tan is PI The general solution is t = 5PI/3+ n PI, where n is any integer t = 2PI/3+ n PI, where n is any integer
How do you solve secx equals 2?
sec x = 2 cos x = 1/2 x = PI/3 and x=5PI/3 The period of cosine is 2PI The general solutions are: x= PI/3 + 2nPI, where n is any integer x = 5PI/3+2nPI, where n is any integer
What is the circumference of a circle of 2.5 cm?
Assumed that the circle's radius is 2.5 cm, then circumference is pi x 2 x 2.5 = 5pi cm
Who can Solve sin(-1)sin((5pi )(7)) with step by Step please )?
Unfortunately, the browser used for posting questions is hopelessly inadequate for mathematics: it strips away most symbols. All that we can see is "sin(-1)sin((5pi )(7))". From that it is not at all clear what the missing symbols (operators) between (5pi ) and (7) might be. There is, therefore no sensible answer. It makes little sense for me to try and guess - I may as well make up my own questions and answer them!All that I can tell you that the principal sin-1 is the inverse for sin over the domain (-pi/2, pi/2). Thus sin-1(sin(x) = x where -pi/2 < x
Volume of a tank 2 ft dia by 5 ft long?
It's a cylinder on its side, so v = pir2h = 5pi = Approx 15.7 cuft
