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sec x = 2

cos x = 1/2

x = PI/3 and x=5PI/3

The period of cosine is 2PI

The general solutions are:

x= PI/3 + 2nPI, where n is any integer

x = 5PI/3+2nPI, where n is any integer

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13y ago
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Q: How do you solve secx equals 2?
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