y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)
The slope (or gradient) of a vertical or horizontal line is zero.
When the equation is given in the standard form: y = mx + c, the gradient is m. So here, y = 7x + 2 means m, the gradient, is 7.
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel
If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.
The equation of the line is y = 7x + 5 The gradient = the slope of the line = dy/dx = 7, in this case. The y-intercept is 5. ========================
17x + 2y = 23 is the equation of a straight line with gradient -8.5 and intercept 11.5
When equation of line is y=-4x+3, Gradient is -4 (as seen from the coefficient of x) and the y-intercept is +3 (point where x=0)
4x+y = 14 will be parallel to the above equation because the slope or gradient remains the same but the y intercept changes.
Select two values of x: (x1 and x2) within the domain. Solve the equation of the line to find the corresponding values for y: (y1 and y2). Then the gradient = (y1 - y2) / (x1 - x2)
Gradient of given line is 2.1/5 = 21/50 So gradient (slope) of perpendicular is -50/21 = -2.381 (to 3 dp)
" y equals 4 equals 3 " is a mathematically meaningless statement, that doesn't lend itself to any standard operations or productive discussion.
the slope is 0
The equation for the slope of a line is y=mx+b
The slope is the gradient which is y2-y1/x2-x1 To find the y int you set the equation of the line equal to zero i think :/
Change the number in front of the X, as that is the gradient.
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)