The general equation of a line is
y = mx + c
If the gradient is 3 then m = 3 so that
y = 3x + c
Since the point (4,1) lies on this line, these coordinates must satisfy the equation.
So 1 = 3*4 + c
ie c = -11
Therefore, the equation is y = 3x - 11
y=3x
Both straight line equations will have the same slope or gradient but the y intercepts wll be different
y = mx + cWhere m is the gradient of the line and c is a constant (the intercept of the line).The equation of a line is typically written asy=mx+b where m is the slope and b is the y-intercept.If you know two points that a line passes through, this page will show you how to find the equation of the line.
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
The equation is: y = 4x-22
y = -4x
y=3x
Both straight line equations will have the same slope or gradient but the y intercepts wll be different
2
Assuming the equation of the given line is y = 3x + 4, its gradient is 3.Therefore the gradient of the required line is 3. The line passes through (3, 1) and so its equation is y - 1 = 3*(x - 3) = 3x - 9 So y = 3x - 8
y = mx + cWhere m is the gradient of the line and c is a constant (the intercept of the line).The equation of a line is typically written asy=mx+b where m is the slope and b is the y-intercept.If you know two points that a line passes through, this page will show you how to find the equation of the line.
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
y=mx+cThe equation of the line is y = mx + c wherem is the gradient of the line and c is the y-interceptThat is, y = 2x + c where c is a constant to be determined.Since the point (3, 2) is on the line,2 = 6 + c so that c = -4So the line is y = 2x - 4
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
y = 0. You can get this from the slope-intercept equation of the line.