An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.
Select two values of x: (x1 and x2) within the domain. Solve the equation of the line to find the corresponding values for y: (y1 and y2). Then the gradient = (y1 - y2) / (x1 - x2)
y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)
The slope is the gradient which is y2-y1/x2-x1 To find the y int you set the equation of the line equal to zero i think :/
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
Change the number in front of the X, as that is the gradient.
y = -4x
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
When the equation is given in the standard form: y = mx + c, the gradient is m. So here, y = 7x + 2 means m, the gradient, is 7.
If you have the equation, yes. If the equation is given in terms of x and y, make y the subject of the equation. That is, expres the equation in the form y = mx + c where m and c are constants. Then the gradient is m.
basically the reciprocal of the original lines gradient is going to be the gradient for the perpendicular line (remember the signs should switch). For example if i had a line with the gradient of 3, then the gradient of the perpendicular line will be -1over3. But if the line had the gradient of -3, then the line perpendicular to that line will have the gradient 1over3.
Gradients can be worked out by: 1. gradient formula, suppose the two points are (x1,y1); (x2,y2) then the gradient=(y2-y1)/(x2-x1) 2. rise/run Intercepts can be found by: 1. to find the x-intercept substitute y=0 into the equation of the line 2. to find the y-intercept substitute x=0 into the equation of the line
you sub the point into the equation you have y=mx+c c=8 so your equation then reads y=mx+8 sub the point (6,12) in and then solve for m 12=m*6+8
y = 2x + 3
Y=2x+c where c is arbitery constant
It is the equation of a straight line in the form of: y = 2x+4
There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient]. The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.
We can find m directly by looking at the change in vertical distance divided by the change in horizontal distance also know as the rise over the run. This give us m, the gradient. Anotther way is if we have the equation of the line, then the slope or gradient can be determined immediately from that. The equation of a line in slope-intercept from is y=mx+b and m represents the slope.
i think you do Vertical/horizontal
divide by the gradient