We will take the height as unknown, so
Unknown = X
Area = 1/2 x X x (12 + 19)
X = A/31
And there you have it. :D.
Half the sum of the parallel sides, times the height between them, that is how you calculate the area of a trapezium.And that is what we learnt at school (to the tune of pop goes the weasel.)______________Here's some more detail, for those who want it:For a trapezoid where h is the height (ie: the distance between the two parallel sides), and a & b are the lengths of the two parallel sides:Area = h (a + b) / 2Proof:If you look at a trapezoid sitting on the longer of its two parallel sides, you will see that it's actually a rectangle in the middle, with a right-angled triangle on each side.The area of the rectangle would be:h x a (where a is the shorter parallel side)For the two right-angled triangles, if c and d are the lengths of the perpendicular sides, then the areas are:(h * c) / 2 and(h * d) / 2So, we add the two triangle areas together, and cancel:(h * c + h * d) / 2= h (c + d) / 2This can be substituted for the following, since in a trapezoid a + c + d = b, hence c + d = b - ah (b - a) /2So, the total area of the trapezoid is the sum of the two formulas:h (b - a) / 2 + h * a(multiply the "h * a" part by 2, and divide be 2 as well, to get a common denominator):= h (b - a) / 2 + 2ha / 2= h (b - a + 2a) / 2= h (b + a) / 2So, there's your proof. A little complicated, but hopefully you get the idea.
Trapezoid.
Half the sum of the parallel sides, times the height between them, that is how you calculate the area of a trapezium.And that is what we learnt at school (to the tune of pop goes the weasel.)______________Here's some more detail, for those who want it:For a trapezoid where h is the height (ie: the distance between the two parallel sides), and a & b are the lengths of the two parallel sides:Area = h (a + b) / 2Proof:If you look at a trapezoid sitting on the longer of its two parallel sides, you will see that it's actually a rectangle in the middle, with a right-angled triangle on each side.The area of the rectangle would be:h x a (where a is the shorter parallel side)For the two right-angled triangles, if c and d are the lengths of the perpendicular sides, then the areas are:(h * c) / 2 and(h * d) / 2So, we add the two triangle areas together, and cancel:(h * c + h * d) / 2= h (c + d) / 2This can be substituted for the following, since in a trapezoid a + c + d = b, hence c + d = b - ah (b - a) /2So, the total area of the trapezoid is the sum of the two formulas:h (b - a) / 2 + h * a(multiply the "h * a" part by 2, and divide be 2 as well, to get a common denominator):= h (b - a) / 2 + 2ha / 2= h (b - a + 2a) / 2= h (b + a) / 2So, there's your proof. A little complicated, but hopefully you get the idea.
For circle area: pi times radius squared. For circle circumference: 2 times pi times radius, for Square area: take the length of one side (doesn't matter which one because they are all equal) and square the number. For parallelogram area: take the base (bottom) and times it by the height (usually going up the middle.) For triangle area: take half of the base or height and times it by the whole base or height. For trapezoid area: the equation is half ( a side plus b side) times height. for rectangle area: width times height.
No, midpoint is the middle point of a line segment. It is the same distance from both ends.
To find the area of a trapezoid you have to use the equations: [Height divided by 2] x [base1+base2] and the answer you get is the area of the trapezoid.
Not too sure of your question but the area of a trapezoid is:- 0.5*(sum of parallel sides)*height Hope the given formula helps you
Half the sum of the parallel sides, times the height between them, that is how you calculate the area of a trapezium.And that is what we learnt at school (to the tune of pop goes the weasel.)______________Here's some more detail, for those who want it:For a trapezoid where h is the height (ie: the distance between the two parallel sides), and a & b are the lengths of the two parallel sides:Area = h (a + b) / 2Proof:If you look at a trapezoid sitting on the longer of its two parallel sides, you will see that it's actually a rectangle in the middle, with a right-angled triangle on each side.The area of the rectangle would be:h x a (where a is the shorter parallel side)For the two right-angled triangles, if c and d are the lengths of the perpendicular sides, then the areas are:(h * c) / 2 and(h * d) / 2So, we add the two triangle areas together, and cancel:(h * c + h * d) / 2= h (c + d) / 2This can be substituted for the following, since in a trapezoid a + c + d = b, hence c + d = b - ah (b - a) /2So, the total area of the trapezoid is the sum of the two formulas:h (b - a) / 2 + h * a(multiply the "h * a" part by 2, and divide be 2 as well, to get a common denominator):= h (b - a) / 2 + 2ha / 2= h (b - a + 2a) / 2= h (b + a) / 2So, there's your proof. A little complicated, but hopefully you get the idea.
split it down the middle
Trapezoid.
If it is an isosceles trapezoid, then there is only one line of symmetry, right down the middle of it from top to bottom. If it is a plain old trapezoid with no congruent sides, then there are no lines of symmetry.
to_find_the_area_of_a_trapezoid:_(b1_plus_b2)_divided_by_2_times_h.._and_thats_itps-------b1---------/ // /_/_____b2__/SECOND ANSWERHere's some more detail, for those who want it:For a trapezoid where h is the height (ie: the distance between the two parallel sides), and a & b are the lengths of the two parallel sides:Area = h (a + b) / 2Proof:If you look at a trapezoid sitting on the longer of its two parallel sides, you will see that it's actually a rectangle in the middle, with a right-angled triangle on each side.The area of the rectangle would be:h x a (where a is the shorter parallel side)For the two right-angled triangles, if c and d are the lengths of the perpendicular sides, then the areas are:(h * c) / 2 and(h * d) / 2So, we add the two triangle areas together, and cancel:(h * c + h * d) / 2= h (c + d) / 2This can be substituted for the following, since in a trapezoid a + c + d = b, hence c + d = b - ah (b - a) /2So, the total area of the trapezoid is the sum of the two formulas:h (b - a) / 2 + h * a(multiply the "h * a" part by 2, and divide be 2 as well, to get a common denominator):= h (b - a) / 2 + 2ha / 2= h (b - a + 2a) / 2= h (b + a) / 2So, there's your proof. A little complicated, but hopefully you get the idea.My god just give them the simple formula (who ever wrote this is stupid)top number+base (bottom number) * height / by 2*=times/=divide
The equator.
Dorothy Irene height
Trapezoid The center of gravity of can be estimated by dividing the trapezoid in two triangles. The center of gravity will be in the intersection between the middle line and the line between the triangles centers of gravity.
Lines going in the same direction. Ex. <-------------------->----------------------> <-------------------->----------------------> The marks in the middle show that the lines are for sure parallel.
It iz kalled the equator