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y = f(x) = (2x + 1)/(x - 1)y*(x - 1) = (2x + 1)

xy - y = 2x + 1

xy - 2x = y + 1

x(y - 2) = y + 1

so x = (y + 1)/(y - 2) assuming y�


So the inverse function is f-1(x) = (x + 1)/(x - 2)

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Q: How do you find the inverse of the function f of x equals 2x plus 1 divide x-1?
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