7x + y + 3 = y7x + 3 = 07x = -3x = -3/7
Here's the kind of process you can use to find out:Write the equation, so you can look at it:7x + 2 = 4x - 3Subtract 4x from each side of the equation:3x + 2 = -3Subtract 2 from each side:3x = -5Divide each side by 3:x = - 5/3
7x-3=3x+8 7x-3x=8+3 4x=11 x=11/4=2.75
7x = 3 x = 3/7
5x - 3y -7x + 2y +3x = (5-7+3)x + (-3+2)y = x - y
Why not? The statement is trivially true, meaning it holds for all values of x.
It is an equation and the value of x is 2
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
x=(y-3)/2
7x - 3 = 3 Subtract 3 from both sides: 7x - 6 = 0 So a = 7 and b = -6
Given 6x + (7x-8) = -5 6x + 7x - 8 = -5 ==> 13x = 3 therefore, x = 3/13
None because without an equal it is not an equation. But if it was in the form of x2+7x+12 = 0 then it would have 2 solutions which are x = -3 and x = -4
To do this equation, you collect like terms. 7x-4x+x-15 is your original equation, you have 3 terms with "'x'" in them, and they are 7x, -4x, and x. 7x + (-4x) +x simplifies to 4x, because 7-4 = 3 + 1 = 4 (the x is really 1x....). After this, you get 4x-15, which is as simplified as this equation can be.
Strictly speaking the above equation is a tautological equation or an IDENTITY. An identity is true for all values of any variables that appear in it. Thus, the above "equation" is true for all value of x. - that is, it has infinitely many solutions.
x2+7x+12=0usually this means to factor the equation.factored this equation would be...(x+3)(x+4)
- 7x + (9x - 3) = - 7x + 9x - 3 = 2x - 3