Add them up and double them. Or double them and add them up. The object has two lengths and two widths. 42 + 42 + 27.5 + 27.5 = 139.
The perimeter is the total distance around - width + width+ length + length.
Length + width = half of perimeter so width = p/2 - length ie (22-12) 10 yards.
None. 42 yards is a length with no width. Therefore it cannot have a perimeter.
To find the width of the rectangle, we can use the formula for the perimeter of a rectangle, which is P = 2(length + width). Given that the perimeter is 18 yards and the length is 6 yards, we can set up the equation: 18 = 2(6 + width). Simplifying this, we get 18 = 12 + 2(width), leading to 6 = 2(width). Therefore, the width is 3 yards.
20 yds
The dimensions are length 50 yards and width 25 yards
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
The width is 3 yards because 3+15+3+15 = 36 yards
It is: 2*(9.5+4) = 27 yards
The length is 200 yards and the width is 48 yards.length + width = 248 yards, and length = (4 x width) + 8 yards.substituting (4 x width) + 8 yards for length,(4 x width) + 8 yards + width = 248 yards;simplifying, width = 240/5 yards = 48 yards;then length = 248 - 48 yards = 200 yards
To find the width, first, convert the length from feet to yards: 24 feet is equal to 8 yards (since 1 yard = 3 feet). The formula for the perimeter of a rectangle is P = 2(length + width). Given that the perimeter is 74 yards, we can set up the equation: 74 = 2(8 + width). Solving for width gives us 74 = 16 + 2(width), so 2(width) = 58, leading to a width of 29 yards.
Length + width = ½ perimeter, ie 42 yards or 126 feet. L = 6 W so w = 126/7 = 18 feet and length is 108 feet ie 36 yards.