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y = 8/x and y = 7+x

So by definition:

7+x = 8/x

Multiply all terms by x:

7x+x2 = 8

Subtract 8 from both sides and form a quadratic equation:

x2+7x-8 = 0

Factor the equation:

(x-1)(x+8) = 0

So x = 1 or x = -8

Substitute the above values into the original equations to find the values of y:

Therefore the points of intersection are (-8,-1) and (1, 8)

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Q: How do you find the points of intersection of the curve and straight line of y equals 8 over x and y equals 7 plus x?
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