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How do you find the points of intersection of the straight line x -2y equals 1 with the curve 3xy - y squared equals 8?
Wiki User
∙ 13y ago
x-2y = 1 => x = 2y+1
3xy-y2 = 8
Substitute x = 2y+1 into the second equation:
3y(2y+1)-y2 = 8
6y2+3y-y2 = 8
5y2+3y-8 = 0
Solving the above with the quadratic equation formula will give y values of: -8/5 and 1
Substitute these values into the first equation to find the values of x:
So the points of intersection are: (3, 1) and (-11/5, -8/5)
Wiki User
∙ 13y ago
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