How do you find the product for this problem 3kminus6 times2k plus 1?

Answer 1

The question is unclear, so the author will provide answers for a number of interpretations:

1. 3k-6(2k+1) = 3k-12k-6=-9k-6=-3(3k+2)

2. 3k-6(2k)+1=3k-12k+1=-9k+1

3. (3k-6)(2k)+1 = 6k^2 -12k + 1 = 6(k-1-sqrt(5/6))(k-1+sqrt(5/6))

4. (3k-6)(2k+1) = 6k^2 - 12k + 3k - 6 = 6k^2 -9k + 6 = 3(2k^2 - 3k + 2)

Line 4 cannot be factorised further. sqrt and ^2 refer to the square root, and squared respectively. Lines 1 and 2 require knowledge of expansion of linear equations, addition of like terms, and factorisation of linear equations. Lines 3 and 4 also require knowledge of addition of like terms, and expansion and factorisation of quadratic equations.

In no case can an exact value for k be determined as we were given an expression rather than an equality.