y^2+8y-9=0
Add the constant 9 to both sides.
y^2+8y=9
Take half of the linear coefficient 8, square it and add it to both sides.
y^2+8y+16=9+16
Now factor the left side and simplify the right side
(y+4)^2=25
Square root both sides.
y+4=+/-5
y=-4+5 or -4-5
y=1 or -9
check your answers.1 works -9 works in the original equation.
The first step would be to find the equation that you are trying to solve!
I'm not familiar with the "bisection method" to find the roots of 2x2-5x+1 = 0 but by completing the square or using the quadratic equation formula you'll find that the solution is: x = (5 + or - the square root of 17) over 4 Hope that helps.
It is not quite clear where a square number fits into the [false] equation 2 = 250
2x2-12x-54 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (2x+6)(x-9) = 0 Therefore: x = -3 or x = 9
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
Completing the square is a technique used to find the zeros/solutions to a polynomial equation; ex) x2 + 2x = 15. To complete the square, one must have a trinomial square on one side of the equation. To do so, add 1 to each side of the previous equation. x2 + 2x + 1 = 16. This will allow you to factor the first side of the equation so that you can take the square root of both sides. (x + 1)(x+1) = 16 => (x + 1)2 = 16. Take the square root of both sides: x + 1 = ± 4. Thus x = -3, 5
Energy E= Pt = I2Rt give I= square -root(E/Rt)
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
x2 = 49 Square root both sides to find the value of x:- x = 7
The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)The idea is to find a number which, when square, equals the given number. For example, asking for the square root of 100 means solving the equation x2 = 100. The solution, in this case, is 10. (Minus 10 is also a solution, but the term "square root" refers to the positive solution in this case.)
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
You're going to want to multiply the square root of 2 by itself to get rid of it. Then you're left with x times 2 equals 18. a = 9√2