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Assume the expression is:
2sin²(x) + cos²(x) = 1
Use this identity to work out the problem: cos²(x) = 1 - sin²(x)
Then:
2sin²(x) + 1 - sin²(x) = 1
sin²(x) + 1 = 1
sin²(x) = 0
sin(x) = 0
Therefore, the solutions are:
x = πk radians where k belongs to the set of integers
In degrees, we obtain:
x = 180l° where l belongs to the set of integers
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Find the second derivative of y equals sin sqaured x?
y = sin2(x) y' = 2sin(x)cos(x) y'' = 2 [ cos(x)cos(x) + sin(x)(-sin(x)) ] = 2 [ cos2(x) - sin2(x) ] = 2 [ 1 - sin2(x) - sin2(x) ] = 2 [ 1 - 2sin2(x) ]
Find all degree solutions 2sin2 6x plus 3sin6x plus 1 equals 0?
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
Find the solution 3x-3y equals 12 and 3x plus y equals 8?
70000000y=35t
Find solution for N equals 3?
N = 3. That really is all there is to it.
Given 2sin s equals cos s find all possible values of sin s?
2sin s = cos s; whence, 4sin2 s = cos2 s = 1 - sin2s, and 5sin2 s = 1. Therefore sin s = ±√0.2 = 0.4472, approx. Check: cos2 s = 1 - 0.2 = 0.8, whence, cos s = ±√0.8 = ±2√0.2 = 2 sin s.
Find the second derivative of y equals sin sqaured x?
y = sin2(x) y' = 2sin(x)cos(x) y'' = 2 [ cos(x)cos(x) + sin(x)(-sin(x)) ] = 2 [ cos2(x) - sin2(x) ] = 2 [ 1 - sin2(x) - sin2(x) ] = 2 [ 1 - 2sin2(x) ]
Find all degree solutions 2sin2 6x plus 3sin6x plus 1 equals 0?
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
What is the second derivative of y equals 2sinx cosx?
y = 2sin(x)cos(x)Use the product rule: uv' + vu' where u is 2sin(x) and v is cos(x) to find first derivative:y' = 2sin(x)(-sin(x)) + cos(x)2cos(x)Simplify:y' = 2cos2(x)-2sin2(x)y' = 2(cos2(x)-sin2(x))Use trig identity cos(2x) = cos2(x)-sin2(x):y' = 2cos(2x)Take second derivative using chain rule:y'' = 2(-sin(2x)cos(2x))Simplify:y'' = -2sin(2x)(2)Simplify:y'' = -4sin(2x)y'' = -4sin(2x)
How would you find a solution to y equals 3x-5x?
8
Find the solution 3x-3y equals 12 and 3x plus y equals 8?
70000000y=35t
Find solution for N equals 3?
N = 3. That really is all there is to it.
What is the solution x plus 2?
to find a solution, you need to also have what x+2 equals.
By inspection find a particular solution to y'' plus 2y equals 10?
y = 5
Given 2sin s equals cos s find all possible values of sin s?
2sin s = cos s; whence, 4sin2 s = cos2 s = 1 - sin2s, and 5sin2 s = 1. Therefore sin s = ±√0.2 = 0.4472, approx. Check: cos2 s = 1 - 0.2 = 0.8, whence, cos s = ±√0.8 = ±2√0.2 = 2 sin s.
How many solutions are there in the equation 2x equals 10?
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
What is the solution of x plus y equals 5?
You have two unknown variables, x and y. You therefore need at least two independent equations to find a solution.
How do you solve 3a plus b equals 1 and a plus b equals to find a common solution?
The second equation is not complete and there is not sufficient information for a solution. It would make no sense for me to guess what a + b equals since, in that case, I may as well start posting my own questions and answering them!
