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The equation 5x -2y = 3 is the same as y = 2.5x -1.5

The perpendicular slope or gradient is the negative reciprocal of 2.5 which is minus 1/2.5

To find the perpendicular equation use y -y1 = m(x -x1) and the point (3, -4)

y - (-4) = -1/2.5(x -3)

y = -1/2.5x +6/5 -4

y = -1/2.5x -14/5 which can be rearranged in the form of 2x +5y +14 = 0

Q: How do you find the straight line equation that passes through the point 3 -4 and is perpendicular to the line 5x -2y equals 3?

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In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0

7x-y-28 = 0

y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.

Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5

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In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0

3x-4y-6 = 0

7x-y-28 = 0

y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.

Find an equati find an equation for the line perpendicular to the line 8x - 8 y equals negative 2 having the same Y intercept as -6x + 2 y equals negative 8

Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5

y=-x

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5

5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.

It would be perpendicular to a line with the equation Y = 1/8 X.

it's a straight line. Through the origin.

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement