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What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
What is the perpendicular bisector equation of the line y equals 17 -3x that spans the parabola of y equals x squared plus 2x -7?
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
What is the perpendicular distance from the point 2 4 to the straight line of y equals 2x plus 10?
Straight line equation: y = 2x+10 Perpendicular equation: y = -1/2x+5 They intersect at: (-2, 6) Length of perpendicular2: (2--2)2+(4-6)2 = 20 and the square root of this is 4.472135955 Therefore distance is 4.472135955 units in length
Is y equals -5x 9 parallel or perpendicular?
y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.
What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
What is the perpendicular distance from the point of 2 4 to the straight line of y equals 2x plus 10 on the Cartesian plane?
The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5
What is the perpendicular distance from the point 2 4 to the straight line equation of y equals 2x plus 10 on the Cartesian plane?
It works out as: 2 times the square root of 5
What is the perpendicular bisector equation of the line y equals 17 -3x that spans the parabola of y equals x squared plus 2x -7?
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
What is the perpendicular distance from the point 2 4 to the straight line of y equals 2x plus 10?
Straight line equation: y = 2x+10 Perpendicular equation: y = -1/2x+5 They intersect at: (-2, 6) Length of perpendicular2: (2--2)2+(4-6)2 = 20 and the square root of this is 4.472135955 Therefore distance is 4.472135955 units in length
What is the perpendicular distance from the coordinates of 7 and 5 to the straight line of 3x plus 4y -16 equals 0 showing key stages of work?
Points: (7, 5) Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (4, 1) Length of perpendicular line: 5
Is y equals -5x 9 parallel or perpendicular?
y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.
What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
What is the perpendicular distance from the point of 2 4 on the Cartesian plane to the straight line equation of y equals 2x plus 10 showing key stages of work?
1 Equation: y = 2x+10 2 Perpendicular equation works out as: 2y = -x+10 3 Point of intersection: (-2, 6) 4 Distance is the square root of: (-2-2)2+(6-4)2 = 2 times sq rt of 5
What is the perpendicular distance from the point 7 5 to the staight line equation 3x plus 4y -16 equals 0 showing key stages of work?
Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Both equations intersect at: (4, 1) Perpendicular distance: square root of (7-4)2+(5-1)2 = 5
The line given by the equation y equals -8x is perpendicular to what line?
It would be perpendicular to a line with the equation Y = 1/8 X.
