Straight line equation: 3x+4y-16 = 0
Perpendicular equation: 4x-3y-13 = 0
Point: (7, 5)
Equations intersect: (4, 1)
Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
Straight line equation: y = 2x+10 Perpendicular equation: y = -1/2x+5 They intersect at: (-2, 6) Length of perpendicular2: (2--2)2+(4-6)2 = 20 and the square root of this is 4.472135955 Therefore distance is 4.472135955 units in length
y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement
The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5
It works out as: 2 times the square root of 5
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
Straight line equation: y = 2x+10 Perpendicular equation: y = -1/2x+5 They intersect at: (-2, 6) Length of perpendicular2: (2--2)2+(4-6)2 = 20 and the square root of this is 4.472135955 Therefore distance is 4.472135955 units in length
Points: (7, 5) Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (4, 1) Length of perpendicular line: 5
y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
1 Equation: y = 2x+10 2 Perpendicular equation works out as: 2y = -x+10 3 Point of intersection: (-2, 6) 4 Distance is the square root of: (-2-2)2+(6-4)2 = 2 times sq rt of 5
Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Both equations intersect at: (4, 1) Perpendicular distance: square root of (7-4)2+(5-1)2 = 5
1 Coordinates: (2, 4) 2 Equation: y = 2x+10 3 Perpendicular equation: y = -0.5+5 4 They intersect at: (-2, 6) 5 Distance is the square root of: (-2, -2)2+(6, -4) = 2*sq rt of 5 = 4.472 to 3 decimal places