Since the perimeter is already known and there are no additional values of sides, nor is the shape known, one would mathematically say the x = 24 cm.
For a square area = side2; perimeter = 4 x side. side2 = 1225 sq cm => side = sqrt(1225) = 35cm => perimeter = 4 x 35cm = 140cm.
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
The answer will depend on what x is.
Length 17 cm. Width 10 cm.
No, that is not correct.
Area = (side)2 = 16 square centimeters Perimeter = 4 x side = 16 centimeters
For a square area = side2; perimeter = 4 x side. side2 = 1225 sq cm => side = sqrt(1225) = 35cm => perimeter = 4 x 35cm = 140cm.
Assuming that it's a rectangle then:- Area = 42*14 = 588 square cm Perimeter = 42+42+14+14 = 112 cm
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
In the value of eight inches, there are approximately twenty point thiry-two centimeters. One can find various calculators on the web to convert these measurements.
The answer will depend on what x is.
2(2x) +2x = 100
The perimeter of a square with a diagonal of 12 centimeters is: 33.9 centimeters.In future, to find out the perimeter of a square when you only know it's diagonal, use Pythagoras or times the diagonal by 2.828427125.This number is irrational, and is like a pi for the diagonals of squares.I call it Tau.It is the relationship between the diagonal of all squares and there perimeter.
Length 17 cm. Width 10 cm.
No, that is not correct.
A decagon has 10 equal sides, so if the perimeter is 120 cm each side must be 12 cm
Knowing only the area, there is no way to find the dimensions without significantly more information.