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What is the area of a rectangle with a perimeter of 30cm?
Let h and w equal the dimensions of the rectangle and A equal its area 2h + 2w = 30 The perimeter of the rectangle is the sum of its sides, two widths and two heights h*w = A The formula for the area of a rectangle We have two equations but three unknown variables. Without more information about this rectangle, it is impossible to solve for the area from the perimeter alone unless this rectangle was specified as being a square (which gives us a third equation, b = h )
A rectangle has perimeter 182 in. and length 52 in. What is the width?
The equation for the perimeter of a rectangle is 2x(a+b) where a is the length and b is the width. We can rewrite the question as the following: 2x(52+b) = 182 If both sides are divided by 2 we get: 52+b = 91 If we subtract 52 from both sides we get: 91 - 52 = 39. Thus the width of the rectangle is 39 in.
A rectangle with area the same as the perimeter?
The perimeter of a rectangle can be expressed as [2 * ( L+ W )]. The area of a rectangle can be expressed as [L * W]. Thus, the equation can be written as:2 * ( L + W ) = L * WThe answer originally posted on this page suggested the only solution is when the shape of the rectangle (four-sided object, opposite sides are equal length) is a square (four-sided object, all sides are equal length) with sides equal to 4.Actually, a 6 x 3 (or 3 x 6) rectangle satisfies the equation, as it has an area and perimeter both equal to 18.Keep in mind this is considering the rectangle sides must have integer values (positive number that is not a fraction), which is actually in accordance with the way the problem was posed going back to its original roots.
What is the equation to find the perimeter of a circle?
Circumference ("perimeter") of a circle = (pi) x (diameter of the circle)
How do you find the area of a rectangle with only the perimeter?
The clever person might realize that, though an infinite number of rectangles can be created with a fixed perimeter, there is a maximum and minimum area that any rectangle formed under the constriction can have. And we can work with that. The minimum area will be "near" zero. (With an area "at" zero, the rectangle will collapse and/or disappear.) The rectangle with "maximumized" area for a fixed perimeter will be a square. Its side (designated by "s") will be one fourth of the perimeter (designated by "p"). If s = p/4 and we use the formula for finding the area (As) of a square substituing our "p/4" for the side length "s" we will get the equation: As = (p/4)2 Our rectangle(s) will all have an area (Ar) within this range: Zero is less than Ar which is less than or equal to (p/4)2 Though we couldn't come up with a precise answer, we came up with the next best thing with the information supplied.
The length of a rectangle is 13.6cm the perimeter of the rectangle is 37.8cm what is the width?
Write an equation for the perimeter, and solve it. Remember that the perimeter is the sum of all four sides.
The length of a rectangle is 4cm longer than the width If the perimeter of the rectangle is 20 centimeters what is the area of the rectangle?
The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters
What is the equation on perimeter?
The perimeter of a plane figure is the length of its boundary. Thus the perimeter of a rectangle of length L and width W is 2L + 2W. The perimeter of a circle is the length of its circumference.
What is the equation for finding length of rectangle?
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
Do you add length plus width to get perimeter?
It depends on the shape, but I'm assuming you mean a square or rectangle. If it is not this shape, edit the question. In this equation L=Length W=Width So, to get the perimeter, you would use this equation: 2L+2W= Perimeter
How do you find the length and width of a rectangle when given the area and perimeter?
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
What are the dimensions of a rectangle that has an area of 600 square cm and a perimeter of 1 m showing work?
I suggest that you do the following:* Convert the meters to centimeters, to have compatible units.* Write the equation for the area of the rectangle. Replace the variable "a" (area) with the known area.* Write the equation for the perimeter of a rectangle. Replace the variable for the perimeter with the known perimeter (in cm).* Use any method to solve the simultaneous equations.Another Answer:-Let the dimensions be x and yIf: 2x+2y = 100 then x+y = 50 and x = 50-yIf: xy = 600 then (50-y)y = 600 and so 50y-y2-600 = 0Solving the quadratic equation: y = 20 or y = 30Therefore by substitution the dimensions are: when y = 20 cm then x = 30 cm
How do you find the length if you have the perimeter and the width?
Equation for perimeter of a rectangle: p = 2l + 2w or: p = 2(l+w) Solve any of the previous equations for the length.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
How do you find length of a rectangle with perimeter and width?
you multiply 2 times the width and 2 times the length ad then add them together. the equation would be 2l+2w=perimeter
What is the area of a rectangle with a perimeter of 30cm?
Let h and w equal the dimensions of the rectangle and A equal its area 2h + 2w = 30 The perimeter of the rectangle is the sum of its sides, two widths and two heights h*w = A The formula for the area of a rectangle We have two equations but three unknown variables. Without more information about this rectangle, it is impossible to solve for the area from the perimeter alone unless this rectangle was specified as being a square (which gives us a third equation, b = h )
The perimeter of a rectangle is 100 centimeters. The length is twice the width. Which equation could you use to find the width of the rectangle in centimeters?
Let the length be 2x and the width be x:- So: 2*(2x+x) = 100 => 6x = 100 => x = 100/6 => x = 16 and 2/3 cm Check: 2*(33 and 1/3 + 16 and 2/3) = 100 cm
